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\begin{document}
	
\thispagestyle{empty}	
	
\begin{center}SANS CALCULATRICE\end{center}\vskip -1cm
	
\hskip-1cm \boxit{4pt}{Minitest N°05}\rightarrowfill\quad\boxit{3pt}{$\begin{matrix}\cr\hbox{Nom :}\hskip 4cm~\hfill\cr\cr \hbox{Prénom :
}\hfill~\cr\;\end{matrix}$}\bigskip

Compléter avec les transformées\bigskip

Si $f(t) = te^{-t}U(t)$ alors $F(p) = $\vskip 1cm

Si $f(t) = tU(t)-(t-3)U(t-3)$ alors $F(p) = $\vskip 1cm

Si $f(t) = t\times e^{-3t}\times U(t)$ alors $F(p) = $\vskip 1cm

Si $f(t) = \sin(2t)\times e^{-3t}\times U(t)$ alors $F(p) = $\vskip 1cm

Si $f(t) = 2\cos(5t)\times e^{-2t}\times U(t)$ alors $F(p) = $\vskip 1cm



Compléter avec les originaux\bigskip

Si $F(p)=\dfrac{1}{p^2+9}$ alors $f(t) = $\vskip 1cm

Si $F(p)=\dfrac{1}{(p+9)^2}$ alors $f(t) = $\vskip 1cm

Si $F(p)=\dfrac{1-e^{-p}}{p^2}$ alors $f(t) = $\vskip 1cm

Si $F(p)=\dfrac{1}{p^2}(1-2e^{-p}+e^{-2p})$ alors $f(t) = $\vskip 1cm

Si $F(p)=\dfrac{p+1}{(p+2)^2+25}$ alors $f(t) = $\vskip 1cm


\newpage

\thispagestyle{empty}	

\begin{center}SANS CALCULATRICE\end{center}\vskip -1cm

\hskip-1cm \boxit{4pt}{Minitest N°05}\rightarrowfill\quad\boxit{3pt}{$\begin{matrix}\cr\hbox{Nom :}\hskip 4cm~\hfill\cr\cr \hbox{Prénom :
		}\hfill~\cr\;\end{matrix}$}\bigskip

Compléter avec les transformées\bigskip

Si $f(t) = te^{-2t}U(t)$ alors $F(p) = $\vskip 1cm

Si $f(t) = tU(t)-(t-4)U(t-4)$ alors $F(p) = $\vskip 1cm

Si $f(t) = t\times e^{-2t}\times U(t)$ alors $F(p) = $\vskip 1cm

Si $f(t) = \sin(3t)\times e^{-2t}\times U(t)$ alors $F(p) = $\vskip 1cm

Si $f(t) = 5\cos(2t)\times e^{-2t}\times U(t)$ alors $F(p) = $\vskip 1cm



Compléter avec les originaux\bigskip

Si $F(p)=\dfrac{2p}{p^2+16}$ alors $f(t) = $\vskip 1cm

Si $F(p)=\dfrac{1}{(p+16)^2}$ alors $f(t) = $\vskip 1cm

Si $F(p)=\dfrac{1-e^{-2p}}{p^2}$ alors $f(t) = $\vskip 1cm

Si $F(p)=\dfrac{1}{p}(1-2e^{-p}+e^{-2p})$ alors $f(t) = $\vskip 1cm

Si $F(p)=\dfrac{p+2}{(p+1)^2+25}$ alors $f(t) = $\vskip 1cm



\end{document} 